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Financial planning
Same idea, four ways to study it. Tap a style and find the one that clicks for you. 📺 Prefer to watch? Videos are on the lesson page.
📘 Two tools from your formula book: a lump sum grows with A = P(1 + i)ⁿ, and regular payments grow with AFV = d[(1 + i)ⁿ − 1] ÷ i  (d = payment, i = rate per period, n = number of periods).

What it is

A financial plan grows money in two ways at once. A lump sum you put in and leave alone, and regular contributions you keep adding every period. Both earn compound interest. Planning is just choosing the tool that matches the question.

The two tools (formula book)

Lump sum
A = P(1 + i)ⁿ
One amount left to grow.
Regular payments
AFV = d[(1 + i)ⁿ − 1] ÷ i
The same deposit d, every period.

d = the payment each period · i = rate per period (decimal) · n = number of periods. To reach a goal, rearrange for d: d = AFV × i ÷ [(1 + i)ⁿ − 1].

Worked example

$200 deposited at the end of each year for 3 years, earning 10% p.a. Find the total.

  1. Set up: d = 200, i = 0.10, n = 3
  2. Substitute: AFV = 200 × [(1.10)³ − 1] ÷ 0.10
  3. Work the bracket: (1.10)³ = 1.331, so [1.331 − 1] ÷ 0.10 = 0.331 ÷ 0.10 = 3.31
  4. Multiply: 200 × 3.31 = $662

Where each deposit ends up

Deposit (end of year)Grows forValue at end
Year 12 years200 × 1.10² = $242
Year 21 year200 × 1.10 = $220
Year 30 years200 × 1 = $200
Total$662

The formula just adds these three up in one line for you.

Watch out

• Use A = P(1 + i)ⁿ for a one-off lump sum, and AFV for repeated payments. Don't mix them.
• i is the rate per period, match it to how often you pay.
• "Reach a goal" questions give you A and ask for d, rearrange, don't guess.
• Round only at the very end.

The payments formula, colour coded

AFV = d × [(1 + i)ⁿ − 1] ÷ i
d = the payment each period [(1+i)ⁿ−1] = the growth engine ÷ i = shares it back per dollar of rate

Each $200 deposit grows a different amount

$242 Year 1 $220 Year 2 $200 Year 3 = $662

Same $200 deposit each year, but the earliest one earns the most interest (the teal cap), because it grows for longest. Add the three: $662.

Two tools, one decision

One amount, left alone
A = P(1 + i)ⁿ
Same deposit, every period
AFV = d[(1 + i)ⁿ − 1] ÷ i

Read the question: is it one lump sum, or a repeating payment? That picks your formula.

Warm up first

Don't read yet, just have a go in your head:

Lump sum or regular payments: "$5,000 invested once for 4 years"?
Lump sum → A = P(1 + i)ⁿ. One amount, left to grow.
Lump sum or regular payments: "$300 added every year for 10 years"?
Regular payments → AFV = d[(1 + i)ⁿ − 1] ÷ i. The same deposit, repeating.
For 10% a year, what number does the bracket use?
i = 0.10, so (1 + i) = 1.10. The bracket is (1.10)ⁿ − 1.

Faded example: $200 a year, 3 years, 10% p.a.

Rung 1 · watch one done fully

d = 200, i = 0.10, n = 3 → AFV = 200 × [(1.10)³ − 1] ÷ 0.10 = 200 × [1.331 − 1] ÷ 0.10 = 200 × 3.31 = $662

Rung 2 · you fill the gaps

d = 200, i = 0.10, n = 3 → AFV = 200 × [(1.10)³ − 1] ÷ 0.10 = 200 × [? − 1] ÷ 0.10 = 200 × ?

Check my gaps
1.331, then 3.31. Final answer $662.
Rung 3 · all you

$100 a year for 2 years at 10% p.a. Write d, i, n, then find AFV. Check below.

Check my answer
d = 100, i = 0.10, n = 2 → AFV = 100 × [(1.10)² − 1] ÷ 0.10 = 100 × [1.21 − 1] ÷ 0.10 = 100 × 2.1 = $210.

Exam-style stretch: reach a goal

You want $2,200 in 2 years, depositing the same amount each year at 20% p.a. How much must you deposit each year?

Show the working
Rearrange for d: d = AFV × i ÷ [(1 + i)ⁿ − 1].
d = 2,200 × 0.20 ÷ [(1.20)² − 1] = 440 ÷ [1.44 − 1] = 440 ÷ 0.44 = $1,000 a year.
Check: 1,000 × [(1.2)² − 1] ÷ 0.2 = 1,000 × 2.2 = $2,200 ✓

Say it back

In one sentence, out loud: how do you know whether to use the lump-sum formula or the payments formula? If you can say it, you've got it.

⚡ Financial planning, one look

Lump sumA = P (1 + i)ⁿ  (one amount, left alone)
Regular payAFV = d[(1 + i)ⁿ − 1] ÷ i  (same deposit each period)
Reach a goald = AFV × i ÷ [(1 + i)ⁿ − 1]
Per periodi = annual rate ÷ payments per year
Example$200/yr, 3 yrs, 10% → 200 × [(1.1)³−1] ÷ 0.1 = $662
Supera regular-payments annuity run over 40+ years
Traplump sum vs payments, pick the right tool · i per period · round at the end
On the Casio(1.1x▢31)÷0.1×200=